7(4z-11)-5(1+2z)=41+3(2z+7

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Solution for 7(4z-11)-5(1+2z)=41+3(2z+7 equation:



7(4z-11)-5(1+2z)=41+3(2z+7
We move all terms to the left:
7(4z-11)-5(1+2z)-(41+3(2z+7)=0
We add all the numbers together, and all the variables
7(4z-11)-5(2z+1)-(41+3(2z+7)=0
We multiply parentheses
28z-10z-(41+3(2z+7)-77-5=0
We add all the numbers together, and all the variables
18z-(41+3(2z+7)-77-5=0

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