7(5+2y)=35+41y

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Solution for 7(5+2y)=35+41y equation: 



7(5+2y)=35+41y

We move all terms to the left:

7(5+2y)-(35+41y)=0

We add all the numbers together, and all the variables

7(2y+5)-(41y+35)=0

We multiply parentheses

14y-(41y+35)+35=0

We get rid of parentheses

14y-41y-35+35=0

We add all the numbers together, and all the variables

-27y=0

y=0/-27

y=0

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