7(5+b)=4(b+8)

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Solution for 7(5+b)=4(b+8) equation: 



7(5+b)=4(b+8)

We move all terms to the left:

7(5+b)-(4(b+8))=0

We add all the numbers together, and all the variables

7(b+5)-(4(b+8))=0

We multiply parentheses

7b-(4(b+8))+35=0



We calculate terms in parentheses: -(4(b+8)), so:

4(b+8)

We multiply parentheses

4b+32

Back to the equation:

-(4b+32)



We get rid of parentheses

7b-4b-32+35=0

We add all the numbers together, and all the variables

3b+3=0

We move all terms containing b to the left, all other terms to the right

3b=-3

b=-3/3

b=-1

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