7(5+c)=6(3+c)

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Solution for 7(5+c)=6(3+c) equation: 



7(5+c)=6(3+c)

We move all terms to the left:

7(5+c)-(6(3+c))=0

We add all the numbers together, and all the variables

7(c+5)-(6(c+3))=0

We multiply parentheses

7c-(6(c+3))+35=0



We calculate terms in parentheses: -(6(c+3)), so:

6(c+3)

We multiply parentheses

6c+18

Back to the equation:

-(6c+18)



We get rid of parentheses

7c-6c-18+35=0

We add all the numbers together, and all the variables

c+17=0

We move all terms containing c to the left, all other terms to the right

c=-17

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