7(5-a)=3(a-5)

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Solution for 7(5-a)=3(a-5) equation: 



7(5-a)=3(a-5)

We move all terms to the left:

7(5-a)-(3(a-5))=0

We add all the numbers together, and all the variables

7(-1a+5)-(3(a-5))=0

We multiply parentheses

-7a-(3(a-5))+35=0



We calculate terms in parentheses: -(3(a-5)), so:

3(a-5)

We multiply parentheses

3a-15

Back to the equation:

-(3a-15)



We get rid of parentheses

-7a-3a+15+35=0

We add all the numbers together, and all the variables

-10a+50=0

We move all terms containing a to the left, all other terms to the right

-10a=-50

a=-50/-10

a=+5

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