7(5b-2)=6(6b-1)

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Solution for 7(5b-2)=6(6b-1) equation: 



7(5b-2)=6(6b-1)

We move all terms to the left:

7(5b-2)-(6(6b-1))=0

We multiply parentheses

35b-(6(6b-1))-14=0



We calculate terms in parentheses: -(6(6b-1)), so:

6(6b-1)

We multiply parentheses

36b-6

Back to the equation:

-(36b-6)



We get rid of parentheses

35b-36b+6-14=0

We add all the numbers together, and all the variables

-1b-8=0

We move all terms containing b to the left, all other terms to the right

-b=8

b=8/-1

b=-8

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