7(5t+1)-10=t-(t+2)

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Solution for 7(5t+1)-10=t-(t+2) equation: 



7(5t+1)-10=t-(t+2)

We move all terms to the left:

7(5t+1)-10-(t-(t+2))=0

We multiply parentheses

35t-(t-(t+2))+7-10=0



We calculate terms in parentheses: -(t-(t+2)), so:

t-(t+2)

We get rid of parentheses

t-t-2

We add all the numbers together, and all the variables

-2

Back to the equation:

-(-2)



We add all the numbers together, and all the variables

35t-1=0

We move all terms containing t to the left, all other terms to the right

35t=1

t=1/35

t=1/35

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