7(5x+8)=12-(1x+4)

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Solution for 7(5x+8)=12-(1x+4) equation: 



7(5x+8)=12-(1x+4)

We move all terms to the left:

7(5x+8)-(12-(1x+4))=0

We add all the numbers together, and all the variables

7(5x+8)-(12-(x+4))=0

We multiply parentheses

35x-(12-(x+4))+56=0



We calculate terms in parentheses: -(12-(x+4)), so:

12-(x+4)

determiningTheFunctionDomain
-(x+4)+12

We get rid of parentheses

-x-4+12

We add all the numbers together, and all the variables

-1x+8

Back to the equation:

-(-1x+8)



We get rid of parentheses

35x+1x-8+56=0

We add all the numbers together, and all the variables

36x+48=0

We move all terms containing x to the left, all other terms to the right

36x=-48

x=-48/36

x=-1+1/3

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