7(5x-3)+10=2(3x-5)+3(5-7x)

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Solution for 7(5x-3)+10=2(3x-5)+3(5-7x) equation: 



7(5x-3)+10=2(3x-5)+3(5-7x)

We move all terms to the left:

7(5x-3)+10-(2(3x-5)+3(5-7x))=0

We add all the numbers together, and all the variables

7(5x-3)-(2(3x-5)+3(-7x+5))+10=0

We multiply parentheses

35x-(2(3x-5)+3(-7x+5))-21+10=0



We calculate terms in parentheses: -(2(3x-5)+3(-7x+5)), so:

2(3x-5)+3(-7x+5)

We multiply parentheses

6x-21x-10+15

We add all the numbers together, and all the variables

-15x+5

Back to the equation:

-(-15x+5)



We add all the numbers together, and all the variables

35x-(-15x+5)-11=0

We get rid of parentheses

35x+15x-5-11=0

We add all the numbers together, and all the variables

50x-16=0

We move all terms containing x to the left, all other terms to the right

50x=16

x=16/50

x=8/25

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