7(6+5(11/4))-27x=32

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Solution for 7(6+5(11/4))-27x=32 equation: 



7(6+5(11/4))-27x=32

We move all terms to the left:

7(6+5(11/4))-27x-(32)=0

determiningTheFunctionDomain
-27x-32+7(6+5(11/4))=0

We add all the numbers together, and all the variables

-27x-32+7(6+5(+11/4))=0

We multiply all the terms by the denominator


-27x*4))-32*4))+7(6+5(+11=0

Wy multiply elements

-432x^3=0

We do not support expression: x^3

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