7(6+y)=-6(3y+-4)+9y

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Solution for 7(6+y)=-6(3y+-4)+9y equation: 



7(6+y)=-6(3y+-4)+9y

We move all terms to the left:

7(6+y)-(-6(3y+-4)+9y)=0

We add all the numbers together, and all the variables

7(y+6)-(-6(3y-4)+9y)=0

We multiply parentheses

7y-(-6(3y-4)+9y)+42=0



We calculate terms in parentheses: -(-6(3y-4)+9y), so:

-6(3y-4)+9y

We add all the numbers together, and all the variables

9y-6(3y-4)

We multiply parentheses

9y-18y+24

We add all the numbers together, and all the variables

-9y+24

Back to the equation:

-(-9y+24)



We get rid of parentheses

7y+9y-24+42=0

We add all the numbers together, and all the variables

16y+18=0

We move all terms containing y to the left, all other terms to the right

16y=-18

y=-18/16

y=-1+1/8

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