7(6-12k)-3=2k-5(11k+3)

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Solution for 7(6-12k)-3=2k-5(11k+3) equation: 



7(6-12k)-3=2k-5(11k+3)

We move all terms to the left:

7(6-12k)-3-(2k-5(11k+3))=0

We add all the numbers together, and all the variables

7(-12k+6)-(2k-5(11k+3))-3=0

We multiply parentheses

-84k-(2k-5(11k+3))+42-3=0



We calculate terms in parentheses: -(2k-5(11k+3)), so:

2k-5(11k+3)

We multiply parentheses

2k-55k-15

We add all the numbers together, and all the variables

-53k-15

Back to the equation:

-(-53k-15)



We add all the numbers together, and all the variables

-84k-(-53k-15)+39=0

We get rid of parentheses

-84k+53k+15+39=0

We add all the numbers together, and all the variables

-31k+54=0

We move all terms containing k to the left, all other terms to the right

-31k=-54

k=-54/-31

k=1+23/31

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