7(6-2c)=5(1-3c)

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Solution for 7(6-2c)=5(1-3c) equation: 



7(6-2c)=5(1-3c)

We move all terms to the left:

7(6-2c)-(5(1-3c))=0

We add all the numbers together, and all the variables

7(-2c+6)-(5(-3c+1))=0

We multiply parentheses

-14c-(5(-3c+1))+42=0



We calculate terms in parentheses: -(5(-3c+1)), so:

5(-3c+1)

We multiply parentheses

-15c+5

Back to the equation:

-(-15c+5)



We get rid of parentheses

-14c+15c-5+42=0

We add all the numbers together, and all the variables

c+37=0

We move all terms containing c to the left, all other terms to the right

c=-37

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