7(6-2x)=3(4x+1)

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Solution for 7(6-2x)=3(4x+1) equation: 



7(6-2x)=3(4x+1)

We move all terms to the left:

7(6-2x)-(3(4x+1))=0

We add all the numbers together, and all the variables

7(-2x+6)-(3(4x+1))=0

We multiply parentheses

-14x-(3(4x+1))+42=0



We calculate terms in parentheses: -(3(4x+1)), so:

3(4x+1)

We multiply parentheses

12x+3

Back to the equation:

-(12x+3)



We get rid of parentheses

-14x-12x-3+42=0

We add all the numbers together, and all the variables

-26x+39=0

We move all terms containing x to the left, all other terms to the right

-26x=-39

x=-39/-26

x=1+1/2

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