7(6-5)+5(b+4)=45

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Solution for 7(6-5)+5(b+4)=45 equation:



7(6-5)+5(b+4)=45
We move all terms to the left:
7(6-5)+5(b+4)-(45)=0
determiningTheFunctionDomain 5(b+4)-45+7(6-5)=0
We add all the numbers together, and all the variables
5(b+4)-45+71=0
We add all the numbers together, and all the variables
5(b+4)+26=0
We multiply parentheses
5b+20+26=0
We add all the numbers together, and all the variables
5b+46=0
We move all terms containing b to the left, all other terms to the right
5b=-46
b=-46/5
b=-9+1/5

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