7(6-x)=2(x-5)-5x

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Solution for 7(6-x)=2(x-5)-5x equation: 



7(6-x)=2(x-5)-5x

We move all terms to the left:

7(6-x)-(2(x-5)-5x)=0

We add all the numbers together, and all the variables

7(-1x+6)-(2(x-5)-5x)=0

We multiply parentheses

-7x-(2(x-5)-5x)+42=0



We calculate terms in parentheses: -(2(x-5)-5x), so:

2(x-5)-5x

We add all the numbers together, and all the variables

-5x+2(x-5)

We multiply parentheses

-5x+2x-10

We add all the numbers together, and all the variables

-3x-10

Back to the equation:

-(-3x-10)



We get rid of parentheses

-7x+3x+10+42=0

We add all the numbers together, and all the variables

-4x+52=0

We move all terms containing x to the left, all other terms to the right

-4x=-52

x=-52/-4

x=+13

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