7(6/5-6)+3/5b=2/5(b+5)

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Solution for 7(6/5-6)+3/5b=2/5(b+5) equation: 



7(6/5-6)+3/5b=2/5(b+5)

We move all terms to the left:

7(6/5-6)+3/5b-(2/5(b+5))=0



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R





Domain of the equation: 5(b+5))!=0

b∈R



We multiply parentheses

3/5b-(2/5(b+5))-42+6/5*7=0

We calculate fractions


(525bb/(875b^2b+(-(2*5b*5*7)/(875b^2b+750b^2/(875b^2b-42=0

We can not solve this equation

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