7(6/5-b)+3/5b=2/5(b+2)

Solution for 7(6/5-b)+3/5b=2/5(b+2) equation:

7(6/5-b)+3/5b=2/5(b+2)

We move all terms to the left:

7(6/5-b)+3/5b-(2/5(b+2))=0


Domain of the equation: 5-b)!=0

We move all terms containing b to the left, all other terms to the right

-b)!=-5

b!=-5/1

b!=-5

b∈R



Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R



Domain of the equation: 5(b+2))!=0

b∈R


We add all the numbers together, and all the variables

7(-1b+6/5)+3/5b-(2/5(b+2))=0

We multiply parentheses

-7b+3/5b-(2/5(b+2))+6/5*7=0

We calculate fractions


(525bb/(875b^2b+(-(2*5b*5*7)/(875b^2b+750b^2/(875b^2b-7b=0

We can not solve this equation