7(6/5-b)+3/5b=2/5(b+5

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Solution for 7(6/5-b)+3/5b=2/5(b+5 equation: 



7(6/5-b)+3/5b=2/5(b+5

We move all terms to the left:

7(6/5-b)+3/5b-(2/5(b+5)=0



Domain of the equation: 5-b)!=0

We move all terms containing b to the left, all other terms to the right

-b)!=-5

b!=-5/1

b!=-5

b∈R





Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R





Domain of the equation: 5(b+5)!=0

b∈R



We add all the numbers together, and all the variables

7(-1b+6/5)+3/5b-(2/5(b+5)=0

We multiply parentheses

-7b+3/5b-(2/5(b+5)+6/5*7=0

We can not solve this equation

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