7(6/7-b)+3/5b=2/5(b+5)

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Solution for 7(6/7-b)+3/5b=2/5(b+5) equation: 



7(6/7-b)+3/5b=2/5(b+5)

We move all terms to the left:

7(6/7-b)+3/5b-(2/5(b+5))=0



Domain of the equation: 7-b)!=0

We move all terms containing b to the left, all other terms to the right

-b)!=-7

b!=-7/1

b!=-7

b∈R





Domain of the equation: 5b!=0

b!=0/5

b!=0

b∈R





Domain of the equation: 5(b+5))!=0

b∈R



We add all the numbers together, and all the variables

7(-1b+6/7)+3/5b-(2/5(b+5))=0

We multiply parentheses

-7b+3/5b-(2/5(b+5))+6/7*7=0

We calculate fractions


(735bb/(1225b^2b+(-(2*5b*7*7)/(1225b^2b+750b^2/(1225b^2b-7b=0

We can not solve this equation

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