7(6t+1)-11=t-(t-3)

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Solution for 7(6t+1)-11=t-(t-3) equation: 



7(6t+1)-11=t-(t-3)

We move all terms to the left:

7(6t+1)-11-(t-(t-3))=0

We multiply parentheses

42t-(t-(t-3))+7-11=0



We calculate terms in parentheses: -(t-(t-3)), so:

t-(t-3)

We get rid of parentheses

t-t+3

We add all the numbers together, and all the variables

3

Back to the equation:

-(3)



We add all the numbers together, and all the variables

42t-7=0

We move all terms containing t to the left, all other terms to the right

42t=7

t=7/42

t=1/6

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