7(6x-10)+21=45

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Solution for 7(6x-10)+21=45 equation:



7(6x-10)+21=45
We move all terms to the left:
7(6x-10)+21-(45)=0
We add all the numbers together, and all the variables
7(6x-10)-24=0
We multiply parentheses
42x-70-24=0
We add all the numbers together, and all the variables
42x-94=0
We move all terms containing x to the left, all other terms to the right
42x=94
x=94/42
x=2+5/21

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