7(6x-3)=2(5x-4)

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Solution for 7(6x-3)=2(5x-4) equation: 



7(6x-3)=2(5x-4)

We move all terms to the left:

7(6x-3)-(2(5x-4))=0

We multiply parentheses

42x-(2(5x-4))-21=0



We calculate terms in parentheses: -(2(5x-4)), so:

2(5x-4)

We multiply parentheses

10x-8

Back to the equation:

-(10x-8)



We get rid of parentheses

42x-10x+8-21=0

We add all the numbers together, and all the variables

32x-13=0

We move all terms containing x to the left, all other terms to the right

32x=13

x=13/32

x=13/32

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