7(6y+1)+(2y+3)/35

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Solution for 7(6y+1)+(2y+3)/35 equation:


y in (-oo:+oo)

7*(6*y+1)+(2*y+3)/35 = 0

(7*35*(6*y+1))/35+(2*y+3)/35 = 0

7*35*(6*y+1)+2*y+3 = 0

1472*y+248 = 0

(1472*y+248)/35 = 0

(1472*y+248)/35 = 0 // * 35

1472*y+248 = 0

1472*y+248 = 0 // - 248

1472*y = -248 // : 1472

y = -248/1472

y = -31/184

y = -31/184

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