7(6y-4)=32

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Solution for 7(6y-4)=32 equation: 



7(6y-4)=32

We move all terms to the left:

7(6y-4)-(32)=0

We multiply parentheses

42y-28-32=0

We add all the numbers together, and all the variables

42y-60=0

We move all terms containing y to the left, all other terms to the right

42y=60

y=60/42

y=1+3/7

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