7(7+9)=8x(8x+6x)

Solution for 7(7+9)=8x(8x+6x) equation:

7(7+9)=8x(8x+6x)

We move all terms to the left:

7(7+9)-(8x(8x+6x))=0

We add all the numbers together, and all the variables

-(8x(+14x))+716=0


We calculate terms in parentheses: -(8x(+14x)), so:

8x(+14x)

We multiply parentheses

112x^2

Back to the equation:

-(112x^2)


a = -112; b = 0; c = +716;
Δ = b2-4ac
Δ = 02-4·(-112)·716
Δ = 320768
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{320768}=\sqrt{256*1253}=\sqrt{256}*\sqrt{1253}=16\sqrt{1253}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{1253}}{2*-112}=\frac{0-16\sqrt{1253}}{-224}
=-\frac{16\sqrt{1253}}{-224}
=-\frac{\sqrt{1253}}{-14}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{1253}}{2*-112}=\frac{0+16\sqrt{1253}}{-224}
=\frac{16\sqrt{1253}}{-224}
=\frac{\sqrt{1253}}{-14}
$