7(7-(2y/3))-5y=20

Solution for 7(7-(2y/3))-5y=20 equation:

7(7-(2y/3))-5y=20

We move all terms to the left:

7(7-(2y/3))-5y-(20)=0

We add all the numbers together, and all the variables

7(7-(+2y/3))-5y-20=0

We add all the numbers together, and all the variables

-5y+7(7-(+2y/3))-20=0

We multiply all the terms by the denominator


-5y*3))+7(7-(+2y-20*3))=0

We add all the numbers together, and all the variables

-5y*3))+7(7-(2y-60))=0

We add all the numbers together, and all the variables

-5y*3))+7(7-(2y=0

Wy multiply elements

-15y^2=0

a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$y=\frac{-b}{2a}=\frac{0}{-30}=0$