7(7-5)+3y=10(y+1)

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Solution for 7(7-5)+3y=10(y+1) equation: 



7(7-5)+3y=10(y+1)

We move all terms to the left:

7(7-5)+3y-(10(y+1))=0

We add all the numbers together, and all the variables

3y-(10(y+1))+72=0



We calculate terms in parentheses: -(10(y+1)), so:

10(y+1)

We multiply parentheses

10y+10

Back to the equation:

-(10y+10)



We get rid of parentheses

3y-10y-10+72=0

We add all the numbers together, and all the variables

-7y+62=0

We move all terms containing y to the left, all other terms to the right

-7y=-62

y=-62/-7

y=8+6/7

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