7(7b-3)=6(8b+11)

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Solution for 7(7b-3)=6(8b+11) equation: 



7(7b-3)=6(8b+11)

We move all terms to the left:

7(7b-3)-(6(8b+11))=0

We multiply parentheses

49b-(6(8b+11))-21=0



We calculate terms in parentheses: -(6(8b+11)), so:

6(8b+11)

We multiply parentheses

48b+66

Back to the equation:

-(48b+66)



We get rid of parentheses

49b-48b-66-21=0

We add all the numbers together, and all the variables

b-87=0

We move all terms containing b to the left, all other terms to the right

b=87

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