7(7b-4)=8(b-2)

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Solution for 7(7b-4)=8(b-2) equation:



7(7b-4)=8(b-2)
We move all terms to the left:
7(7b-4)-(8(b-2))=0
We multiply parentheses
49b-(8(b-2))-28=0
We calculate terms in parentheses: -(8(b-2)), so:
8(b-2)
We multiply parentheses
8b-16
Back to the equation:
-(8b-16)
We get rid of parentheses
49b-8b+16-28=0
We add all the numbers together, and all the variables
41b-12=0
We move all terms containing b to the left, all other terms to the right
41b=12
b=12/41
b=12/41

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