7(7b-4)=8(b-2)

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Solution for 7(7b-4)=8(b-2) equation: 



7(7b-4)=8(b-2)

We move all terms to the left:

7(7b-4)-(8(b-2))=0

We multiply parentheses

49b-(8(b-2))-28=0



We calculate terms in parentheses: -(8(b-2)), so:

8(b-2)

We multiply parentheses

8b-16

Back to the equation:

-(8b-16)



We get rid of parentheses

49b-8b+16-28=0

We add all the numbers together, and all the variables

41b-12=0

We move all terms containing b to the left, all other terms to the right

41b=12

b=12/41

b=12/41

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