7(7c+1)-4c=12(3c-2)

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Solution for 7(7c+1)-4c=12(3c-2) equation: 



7(7c+1)-4c=12(3c-2)

We move all terms to the left:

7(7c+1)-4c-(12(3c-2))=0

We add all the numbers together, and all the variables

-4c+7(7c+1)-(12(3c-2))=0

We multiply parentheses

-4c+49c-(12(3c-2))+7=0



We calculate terms in parentheses: -(12(3c-2)), so:

12(3c-2)

We multiply parentheses

36c-24

Back to the equation:

-(36c-24)



We add all the numbers together, and all the variables

45c-(36c-24)+7=0

We get rid of parentheses

45c-36c+24+7=0

We add all the numbers together, and all the variables

9c+31=0

We move all terms containing c to the left, all other terms to the right

9c=-31

c=-31/9

c=-3+4/9

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