7(7c+1)-4c=13(3c-7)

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Solution for 7(7c+1)-4c=13(3c-7) equation:



7(7c+1)-4c=13(3c-7)
We move all terms to the left:
7(7c+1)-4c-(13(3c-7))=0
We add all the numbers together, and all the variables
-4c+7(7c+1)-(13(3c-7))=0
We multiply parentheses
-4c+49c-(13(3c-7))+7=0
We calculate terms in parentheses: -(13(3c-7)), so:
13(3c-7)
We multiply parentheses
39c-91
Back to the equation:
-(39c-91)
We add all the numbers together, and all the variables
45c-(39c-91)+7=0
We get rid of parentheses
45c-39c+91+7=0
We add all the numbers together, and all the variables
6c+98=0
We move all terms containing c to the left, all other terms to the right
6c=-98
c=-98/6
c=-16+1/3

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