7(7c+1)4c=13(3c-2)

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Solution for 7(7c+1)4c=13(3c-2) equation: 



7(7c+1)4c=13(3c-2)

We move all terms to the left:

7(7c+1)4c-(13(3c-2))=0

We multiply parentheses

196c^2+28c-(13(3c-2))=0



We calculate terms in parentheses: -(13(3c-2)), so:

13(3c-2)

We multiply parentheses

39c-26

Back to the equation:

-(39c-26)



We get rid of parentheses

196c^2+28c-39c+26=0

We add all the numbers together, and all the variables

196c^2-11c+26=0

a = 196; b = -11; c = +26;
Δ = b2-4ac
Δ = -112-4·196·26
Δ = -20263
Delta is less than zero, so there is no solution for the equation

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