7(7c+1)=13(3c-2)

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Solution for 7(7c+1)=13(3c-2) equation:


Simplifying
7(7c + 1) = 13(3c + -2)

Reorder the terms:
7(1 + 7c) = 13(3c + -2)
(1 * 7 + 7c * 7) = 13(3c + -2)
(7 + 49c) = 13(3c + -2)

Reorder the terms:
7 + 49c = 13(-2 + 3c)
7 + 49c = (-2 * 13 + 3c * 13)
7 + 49c = (-26 + 39c)

Solving
7 + 49c = -26 + 39c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-39c' to each side of the equation.
7 + 49c + -39c = -26 + 39c + -39c

Combine like terms: 49c + -39c = 10c
7 + 10c = -26 + 39c + -39c

Combine like terms: 39c + -39c = 0
7 + 10c = -26 + 0
7 + 10c = -26

Add '-7' to each side of the equation.
7 + -7 + 10c = -26 + -7

Combine like terms: 7 + -7 = 0
0 + 10c = -26 + -7
10c = -26 + -7

Combine like terms: -26 + -7 = -33
10c = -33

Divide each side by '10'.
c = -3.3

Simplifying
c = -3.3

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