7(7c+10)-4c=13(3c-2)

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Solution for 7(7c+10)-4c=13(3c-2) equation:



7(7c+10)-4c=13(3c-2)
We move all terms to the left:
7(7c+10)-4c-(13(3c-2))=0
We add all the numbers together, and all the variables
-4c+7(7c+10)-(13(3c-2))=0
We multiply parentheses
-4c+49c-(13(3c-2))+70=0
We calculate terms in parentheses: -(13(3c-2)), so:
13(3c-2)
We multiply parentheses
39c-26
Back to the equation:
-(39c-26)
We add all the numbers together, and all the variables
45c-(39c-26)+70=0
We get rid of parentheses
45c-39c+26+70=0
We add all the numbers together, and all the variables
6c+96=0
We move all terms containing c to the left, all other terms to the right
6c=-96
c=-96/6
c=-16

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