7(7c+7)-4c=13(3c-2)

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Solution for 7(7c+7)-4c=13(3c-2) equation: 



7(7c+7)-4c=13(3c-2)

We move all terms to the left:

7(7c+7)-4c-(13(3c-2))=0

We add all the numbers together, and all the variables

-4c+7(7c+7)-(13(3c-2))=0

We multiply parentheses

-4c+49c-(13(3c-2))+49=0



We calculate terms in parentheses: -(13(3c-2)), so:

13(3c-2)

We multiply parentheses

39c-26

Back to the equation:

-(39c-26)



We add all the numbers together, and all the variables

45c-(39c-26)+49=0

We get rid of parentheses

45c-39c+26+49=0

We add all the numbers together, and all the variables

6c+75=0

We move all terms containing c to the left, all other terms to the right

6c=-75

c=-75/6

c=-12+1/2

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