7(7c-1)+4c=13(3c+-2)

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Solution for 7(7c-1)+4c=13(3c+-2) equation: 



7(7c-1)+4c=13(3c+-2)

We move all terms to the left:

7(7c-1)+4c-(13(3c+-2))=0

We add all the numbers together, and all the variables

7(7c-1)+4c-(13(3c-2))=0

We add all the numbers together, and all the variables

4c+7(7c-1)-(13(3c-2))=0

We multiply parentheses

4c+49c-(13(3c-2))-7=0



We calculate terms in parentheses: -(13(3c-2)), so:

13(3c-2)

We multiply parentheses

39c-26

Back to the equation:

-(39c-26)



We add all the numbers together, and all the variables

53c-(39c-26)-7=0

We get rid of parentheses

53c-39c+26-7=0

We add all the numbers together, and all the variables

14c+19=0

We move all terms containing c to the left, all other terms to the right

14c=-19

c=-19/14

c=-1+5/14

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