7(7x-5)=2(6+x)

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Solution for 7(7x-5)=2(6+x) equation: 



7(7x-5)=2(6+x)

We move all terms to the left:

7(7x-5)-(2(6+x))=0

We add all the numbers together, and all the variables

7(7x-5)-(2(x+6))=0

We multiply parentheses

49x-(2(x+6))-35=0



We calculate terms in parentheses: -(2(x+6)), so:

2(x+6)

We multiply parentheses

2x+12

Back to the equation:

-(2x+12)



We get rid of parentheses

49x-2x-12-35=0

We add all the numbers together, and all the variables

47x-47=0

We move all terms containing x to the left, all other terms to the right

47x=47

x=47/47

x=1

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