7(8-4x)=32-4x

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Solution for 7(8-4x)=32-4x equation: 



7(8-4x)=32-4x

We move all terms to the left:

7(8-4x)-(32-4x)=0

We add all the numbers together, and all the variables

7(-4x+8)-(-4x+32)=0

We multiply parentheses

-28x-(-4x+32)+56=0

We get rid of parentheses

-28x+4x-32+56=0

We add all the numbers together, and all the variables

-24x+24=0

We move all terms containing x to the left, all other terms to the right

-24x=-24

x=-24/-24

x=1

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