7(8b+2)=32-5b

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Solution for 7(8b+2)=32-5b equation:



7(8b+2)=32-5b
We move all terms to the left:
7(8b+2)-(32-5b)=0
We add all the numbers together, and all the variables
7(8b+2)-(-5b+32)=0
We multiply parentheses
56b-(-5b+32)+14=0
We get rid of parentheses
56b+5b-32+14=0
We add all the numbers together, and all the variables
61b-18=0
We move all terms containing b to the left, all other terms to the right
61b=18
b=18/61
b=18/61

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