7(8x-3)+5(3x-8)=10(7x+4)+x

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Solution for 7(8x-3)+5(3x-8)=10(7x+4)+x equation: 



7(8x-3)+5(3x-8)=10(7x+4)+x

We move all terms to the left:

7(8x-3)+5(3x-8)-(10(7x+4)+x)=0

We multiply parentheses

56x+15x-(10(7x+4)+x)-21-40=0



We calculate terms in parentheses: -(10(7x+4)+x), so:

10(7x+4)+x

We add all the numbers together, and all the variables

x+10(7x+4)

We multiply parentheses

x+70x+40

We add all the numbers together, and all the variables

71x+40

Back to the equation:

-(71x+40)



We add all the numbers together, and all the variables

71x-(71x+40)-61=0

We get rid of parentheses

71x-71x-40-61=0

We add all the numbers together, and all the variables

-101!=0

There is no solution for this equation

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