7(9+x)/4=(5+8x+2)/6

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Solution for 7(9+x)/4=(5+8x+2)/6 equation:



7(9+x)/4=(5+8x+2)/6
We move all terms to the left:
7(9+x)/4-((5+8x+2)/6)=0
We add all the numbers together, and all the variables
7(x+9)/4-((8x+7)/6)=0
We calculate fractions
7x/()+(-((8x+7)*4)/()=0
We calculate terms in parentheses: +(-((8x+7)*4)/(), so:
-((8x+7)*4)/(
We multiply all the terms by the denominator
-((8x+7)*4)
We calculate terms in parentheses: -((8x+7)*4), so:
(8x+7)*4
We multiply parentheses
32x+28
Back to the equation:
-(32x+28)
We get rid of parentheses
-32x-28
Back to the equation:
+(-32x-28)
We get rid of parentheses
7x/()-32x-28=0
We multiply all the terms by the denominator
7x-32x*()-28*()=0
We add all the numbers together, and all the variables
7x-32x*()=0

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