7(9x-2)+3=-3(4x+1)=6

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Solution for 7(9x-2)+3=-3(4x+1)=6 equation: 



7(9x-2)+3=-3(4x+1)=6

We move all terms to the left:

7(9x-2)+3-(-3(4x+1))=0

We multiply parentheses

63x-(-3(4x+1))-14+3=0



We calculate terms in parentheses: -(-3(4x+1)), so:

-3(4x+1)

We multiply parentheses

-12x-3

Back to the equation:

-(-12x-3)



We add all the numbers together, and all the variables

63x-(-12x-3)-11=0

We get rid of parentheses

63x+12x+3-11=0

We add all the numbers together, and all the variables

75x-8=0

We move all terms containing x to the left, all other terms to the right

75x=8

x=8/75

x=8/75

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