7(9x-3)=16+6x

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Solution for 7(9x-3)=16+6x equation: 



7(9x-3)=16+6x

We move all terms to the left:

7(9x-3)-(16+6x)=0

We add all the numbers together, and all the variables

7(9x-3)-(6x+16)=0

We multiply parentheses

63x-(6x+16)-21=0

We get rid of parentheses

63x-6x-16-21=0

We add all the numbers together, and all the variables

57x-37=0

We move all terms containing x to the left, all other terms to the right

57x=37

x=37/57

x=37/57

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