7(9x-4)=2(4x+3)

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Solution for 7(9x-4)=2(4x+3) equation: 



7(9x-4)=2(4x+3)

We move all terms to the left:

7(9x-4)-(2(4x+3))=0

We multiply parentheses

63x-(2(4x+3))-28=0



We calculate terms in parentheses: -(2(4x+3)), so:

2(4x+3)

We multiply parentheses

8x+6

Back to the equation:

-(8x+6)



We get rid of parentheses

63x-8x-6-28=0

We add all the numbers together, and all the variables

55x-34=0

We move all terms containing x to the left, all other terms to the right

55x=34

x=34/55

x=34/55

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