7(9x-5)+7=42x-28

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Solution for 7(9x-5)+7=42x-28 equation: 



7(9x-5)+7=42x-28

We move all terms to the left:

7(9x-5)+7-(42x-28)=0

We multiply parentheses

63x-(42x-28)-35+7=0

We get rid of parentheses

63x-42x+28-35+7=0

We add all the numbers together, and all the variables

21x=0

x=0/21

x=0

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