7(9x-5)=41

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Solution for 7(9x-5)=41 equation: 



7(9x-5)=41

We move all terms to the left:

7(9x-5)-(41)=0

We multiply parentheses

63x-35-41=0

We add all the numbers together, and all the variables

63x-76=0

We move all terms containing x to the left, all other terms to the right

63x=76

x=76/63

x=1+13/63

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