7(C+2)=3C-5+4C+9

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Solution for 7(C+2)=3C-5+4C+9 equation: 


Simplifying
7(C + 2) = 3C + -5 + 4C + 9

Reorder the terms:
7(2 + C) = 3C + -5 + 4C + 9
(2 * 7 + C * 7) = 3C + -5 + 4C + 9
(14 + 7C) = 3C + -5 + 4C + 9

Reorder the terms:
14 + 7C = -5 + 9 + 3C + 4C

Combine like terms: -5 + 9 = 4
14 + 7C = 4 + 3C + 4C

Combine like terms: 3C + 4C = 7C
14 + 7C = 4 + 7C

Add '-7C' to each side of the equation.
14 + 7C + -7C = 4 + 7C + -7C

Combine like terms: 7C + -7C = 0
14 + 0 = 4 + 7C + -7C
14 = 4 + 7C + -7C

Combine like terms: 7C + -7C = 0
14 = 4 + 0
14 = 4

Solving
14 = 4

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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