7(C-5)=6-(C+1)

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Solution for 7(C-5)=6-(C+1) equation:


Simplifying
7(C + -5) = 6 + -1(C + 1)

Reorder the terms:
7(-5 + C) = 6 + -1(C + 1)
(-5 * 7 + C * 7) = 6 + -1(C + 1)
(-35 + 7C) = 6 + -1(C + 1)

Reorder the terms:
-35 + 7C = 6 + -1(1 + C)
-35 + 7C = 6 + (1 * -1 + C * -1)
-35 + 7C = 6 + (-1 + -1C)

Combine like terms: 6 + -1 = 5
-35 + 7C = 5 + -1C

Solving
-35 + 7C = 5 + -1C

Solving for variable 'C'.

Move all terms containing C to the left, all other terms to the right.

Add 'C' to each side of the equation.
-35 + 7C + C = 5 + -1C + C

Combine like terms: 7C + C = 8C
-35 + 8C = 5 + -1C + C

Combine like terms: -1C + C = 0
-35 + 8C = 5 + 0
-35 + 8C = 5

Add '35' to each side of the equation.
-35 + 35 + 8C = 5 + 35

Combine like terms: -35 + 35 = 0
0 + 8C = 5 + 35
8C = 5 + 35

Combine like terms: 5 + 35 = 40
8C = 40

Divide each side by '8'.
C = 5

Simplifying
C = 5

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