7(X+3)=9(2x-5)

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Solution for 7(X+3)=9(2x-5) equation: 



7(X+3)=9(2X-5)

We move all terms to the left:

7(X+3)-(9(2X-5))=0

We multiply parentheses

7X-(9(2X-5))+21=0



We calculate terms in parentheses: -(9(2X-5)), so:

9(2X-5)

We multiply parentheses

18X-45

Back to the equation:

-(18X-45)



We get rid of parentheses

7X-18X+45+21=0

We add all the numbers together, and all the variables

-11X+66=0

We move all terms containing X to the left, all other terms to the right

-11X=-66

X=-66/-11

X=+6

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